No. 01Calculus Volume 1 · Chapter 2 · Limits

Section 2.2 · Field notes

The Limit of
a Function

Where a function is headed near a point — even when the point can't be trusted

CoverbookSHelf · §2.2
No. 02The opening problem

A value the formula can't give you

Closing in on x=2x = 2

Graph of f(x)=x24x2f(x)=\dfrac{x^2-4}{x-2}. At x=2x=2 it has no value (you'd divide by zero). So where is the graph headed as xx nears 2? Tabulate just below and just above.

from leftf(x)f(x)from rightf(x)f(x)
1335
1.93.92.14.1
1.993.992.014.01
1.9993.9992.0014.001
1.99993.99992.00014.0001

Table 2.2.1: Both columns close in on 44.

From both sides f(x)f(x) heads toward 4 — even though f(2)=00f(2)=\tfrac{0}{0} has no value. It heads there without ever arriving.

Figure 2.2.1: f(x)=x24x2f(x)=\dfrac{x^2-4}{x-2} — the line y=x+2y=x+2 with (2,4)(2,4) punched out.

The opening problem02 / 23
No. 03Contents

By the end of this section you will be able to

Learning objectives

  1. Describe the limit of a function in correct notation definition
  2. Use a table of values to estimate a limit — or see it fail Table 2.2.2
  3. Use a graph to estimate a limit — or see it fail Figure 2.2.4
  4. Define one-sided limits and give examples Def 2.2.2
  5. Relate one-sided and two-sided limits Thm 2.2.2
  6. Describe an infinite limit in correct notation Def 2.2.3
  7. Define a vertical asymptote Def 2.2.4
Contents03 / 23
No. 04The big idea

Why we approach instead of substitute

Why the hole?

Factor and cancel:

x24x2=(x2)(x+2)x2=x+2for x2.\frac{x^2-4}{x-2}=\frac{(x-2)(x+2)}{x-2}=x+2 \quad\text{for } x \ne 2.

So ff is the line y=x+2y=x+2 with the single point (2,4)(2,4) punched out. The cancellation is only legal for x2x \ne 2 — which is why we approach the point instead of substituting it. (Evaluating limits exactly by factoring is the work of §2.3.)

Big idea

A limit reads where a function is headed, not where it is — like reading which way a friend is walking through a crowd, even when you can't see exactly where they stand.

The big idea04 / 23
No. 05The definition

Definition 2.2.1 — Limit (intuitive)

Definition 2.2.1 — Limit

Let f(x)f(x) be defined for all xx in an open interval containing aa, except possibly at aa itself, and let LL be a real number. If all values of f(x)f(x) approach LL as the values of x (a)x\ (\ne a) approach aa, then the limit of f(x)f(x) as xx approaches aa is LL:

limxaf(x)=L.\lim_{x \to a} f(x) = L.

Open interval containing a, with a shaded neighborhood band around a

Figure 2.2.2: The limit reports the neighborhood (shaded band around aa), not the value at the point.

Read it: for f(x)=x24x2f(x)=\dfrac{x^2-4}{x-2}, the value f(2)f(2) does not exist — yet limx2f(x)=4\displaystyle\lim_{x \to 2} f(x) = 4.

The definition05 / 23
No. 06Estimating from a table

Example 2.2.1 — A limit from a table

Evaluate limx0sinxx\displaystyle\lim_{x \to 0}\frac{\sin x}{x} using a table. The function is even, so the left and right columns match.

xxsinx/x\sin x / x
±0.1\pm 0.10.99833
±0.01\pm 0.010.99998
±0.001\pm 0.0010.9999998

Table 2.2.2: Both sides march toward 1.

Estimate

limx0sinxx=1.\lim_{x \to 0}\frac{\sin x}{x}=1.

Graph of sin(x)/x approaching height 1 as x approaches 0

Figure 2.2.3: y=sinxxy=\dfrac{\sin x}{x} settles on height 1 at x=0x=0.

Estimating from a table06 / 23
No. 07Estimating from a table

Try It Now 2.2.1 — Your turn

Estimate limx11x1x1\displaystyle\lim_{x \to 1}\frac{\tfrac{1}{x}-1}{x-1}

Simplify first: 1x1x1=(x1)x(x1)=1x\dfrac{\tfrac{1}{x}-1}{x-1}=\dfrac{-(x-1)}{x(x-1)}=-\dfrac{1}{x} for x1x \ne 1.

Answer

Both columns march toward 1-1, so limx11x1x1=1.\lim_{x \to 1}\frac{\tfrac{1}{x}-1}{x-1}=-1.

xxf(x)f(x)xxf(x)f(x)
0.9-1.11111.1-0.9091
0.99-1.01011.01-0.9901
0.999-1.00101.001-0.9990

Table 2.2.3: Both sides close in on 1-1.

Estimating from a table07 / 23
No. 08Estimating from a graph

Example 2.2.3 — A limit from a graph

For the function g(x)g(x) shown, evaluate limx1g(x)\displaystyle\lim_{x \to -1} g(x).

Read the neighborhood

The marked point shows g(1)=4g(-1)=4, but the curve approaches height 3 from both sides: limx1g(x)=3.\lim_{x \to -1} g(x)=3.

The limit and the function value are allowed to disagree — the limit reports the neighborhood, not the isolated point.

Graph of g(x): curve approaches 3 near x=-1 while the plotted point sits at 4

Figure 2.2.4: g(1)=4g(-1)=4, yet limx1g(x)=3\displaystyle\lim_{x\to-1}g(x)=3.

Estimating from a graph08 / 23
No. 09Two building blocks

Theorem 2.2.1 — Two important limits

From estimates to building blocks

Tables and graphs rest on guesswork — a trend read, not a value proved. §2.3 builds algebraic limit laws that compute limits exactly. Two limits are so basic that every one of those laws leans on them.

Theorem 2.2.1 — Two important limits

For any real number aa and constant cc:

limxax=aandlimxac=c.\lim_{x \to a} x = a \qquad\text{and}\qquad \lim_{x \to a} c = c.

The identity function f(x)=xf(x)=x marches along with xx; a constant function never moves. These are the atomic building blocks inside every limit law from here on.

Two building blocks09 / 23
No. 10When a limit fails

Two ways to fail · Example 2.2.4

A two-sided limit exists only if f(x)f(x) approaches a single real number from both sides. It can miss in two ways: oscillation (bounces forever) or blow-up (shoots to ±\pm\infty). Both read DNE for now.

Evaluate limx0sin ⁣(1x)\displaystyle\lim_{x \to 0}\sin\!\left(\tfrac{1}{x}\right). As x0x \to 0, 1/x1/x blows up, so sin(1/x)\sin(1/x) oscillates faster and faster — never settling.

Oscillation → DNE

Along x=2π,23π,25π,x=\tfrac{2}{\pi},\tfrac{2}{3\pi},\tfrac{2}{5\pi},\dots the value cycles 1,1,1,1,1,-1,1,-1,\dots. Different paths give different values, so limx0sin ⁣(1x)\displaystyle\lim_{x \to 0}\sin\!\left(\tfrac{1}{x}\right) DNE.

Graph of sin(1/x) oscillating ever faster near x=0

Figure 2.2.5: sin(1/x)\sin(1/x) oscillates without bound as x0x\to 0.

When a limit fails10 / 23
No. 11When DNE hides the story

Some failures deserve their own notation

Saying "the limit does not exist" sometimes throws away useful information.

sin(1/x)\sin(1/x) genuinely wandered — nothing more to say. But recall g(x)=x2x2g(x)=\dfrac{|x-2|}{x-2}: it settles cleanly on 1-1 from the left and +1+1 from the right.

The two-sided limit fails, yet each side is perfectly well-behaved. That deserves its own notation.

Figure 2.2.6: g(x)=x2x2g(x)=\dfrac{|x-2|}{x-2} — clean on each side, a jump at x=2x=2.

When DNE hides the story11 / 23
No. 12One-sided limits

Definition 2.2.2 — One-sided limits

One-sided limits

Definition 2.2.2 — Left and right limits

From the left. If f(x)f(x) approaches LL as x (x<a)x\ (x < a) approaches aa: limxaf(x)=L.\displaystyle\lim_{x \to a^-} f(x) = L.

From the right. If f(x)f(x) approaches LL as x (x>a)x\ (x > a) approaches aa: limxa+f(x)=L.\displaystyle\lim_{x \to a^+} f(x) = L.

Example: for g(x)=x2x2g(x)=\dfrac{|x-2|}{x-2} the two-sided limit DNE, but the sides are clean — limx2g(x)=1\displaystyle\lim_{x \to 2^-} g(x) = -1 and limx2+g(x)=1\displaystyle\lim_{x \to 2^+} g(x) = 1.

One-sided limits12 / 23
No. 13One-sided limits

Example 2.2.5 — Evaluating one-sided limits

f(x)={x+1if x<2,x24if x2.f(x)=\begin{cases} x+1 & \text{if } x < 2,\\[2pt] x^2-4 & \text{if } x \ge 2.\end{cases}

Use the correct branch on each side: limx2f(x)=3,limx2+f(x)=0.\lim_{x \to 2^-} f(x) = 3,\qquad \lim_{x \to 2^+} f(x) = 0.

Sides disagree → DNE

Because the side limits differ, limx2f(x)\displaystyle\lim_{x \to 2} f(x) DNE — the graph jumps at x=2x=2.

Piecewise graph jumping from 3 to 0 at x=2

Figure 2.2.7: A jump at x=2x=2: left limit 3, right limit 0.

One-sided limits13 / 23
No. 14One-sided limits

Try It Now 2.2.4 — Your turn

One-sided limits of x24x2\dfrac{|x^2-4|}{x-2} at x=2x=2

Factor: x24=x2x+2|x^2-4| = |x-2|\,|x+2|.

  • For x>2x > 2: x24x2x+2=4\quad \dfrac{|x^2-4|}{x-2} \to |x+2| = 4.
  • For x<2x < 2: x24x2x+2=4\quad \dfrac{|x^2-4|}{x-2} \to -|x+2| = -4.

Answer

limx2x24x2=4,limx2+x24x2=4.\lim_{x \to 2^-}\frac{|x^2-4|}{x-2}=-4,\qquad \lim_{x \to 2^+}\frac{|x^2-4|}{x-2}=4.Left side 4-4; right side +4+4; two-sided DNE.

One-sided limits14 / 23
No. 15One-sided ⟺ two-sided

Theorem 2.2.2 — Relating one- and two-sided limits

When the two sides shake hands

Theorem 2.2.2 — One-sided and two-sided limits

limxaf(x)=L        limxaf(x)=L  and  limxa+f(x)=L.\lim_{x \to a} f(x) = L \;\iff\; \lim_{x \to a^-} f(x) = L \ \text{ and } \ \lim_{x \to a^+} f(x) = L.

The two-sided limit exists exactly when the two side limits agree on the same value. If they disagree, the two-sided limit does not exist.

One-sided ⟺ two-sided15 / 23
No. 16Back to the blow-up

Recording how a limit fails

Every function so far stayed bounded near its trouble point. But the third opening function never settles:

h(x)=1(x2)2  +as x2.h(x)=\frac{1}{(x-2)^2}\ \longrightarrow\ +\infty \quad\text{as } x \to 2.

This is the blow-up failure flagged earlier. Rather than write "DNE", we record how it fails — with the symbol \infty.

Figure 2.2.8: h(x)=1(x2)2h(x)=\dfrac{1}{(x-2)^2} climbs to ++\infty on both sides of x=2x=2.

Back to the blow-up16 / 23
No. 17Naming the blow-up

Definitions 2.2.3 & 2.2.4

Definition 2.2.3 — Infinite limits

If f(x)f(x) increases without bound as xax \to a: limxaf(x)=+\displaystyle\lim_{x \to a} f(x) = +\infty; if it decreases without bound, limxaf(x)=\displaystyle\lim_{x \to a} f(x) = -\infty. The same applies to xax \to a^- and xa+x \to a^+.

Definition 2.2.4 — Vertical asymptote

The line x=ax = a is a vertical asymptote of f(x)f(x) if any one holds: limxaf(x)=±,  limxa+f(x)=±,  limxaf(x)=±.\lim_{x \to a^-} f(x) = \pm\infty,\ \ \lim_{x \to a^+} f(x) = \pm\infty,\ \ \lim_{x \to a} f(x) = \pm\infty.

Writing ±\pm\infty records how the limit fails — by blowing up — instead of just "DNE". (Infinity describes behavior; it is not a real-number value.) Example: h(x)=1(x2)2h(x)=\dfrac{1}{(x-2)^2} has limx2h(x)=+\displaystyle\lim_{x\to 2}h(x)=+\infty, so x=2x=2 is a vertical asymptote.

Naming the blow-up17 / 23
No. 18An infinite limit

Example 2.2.6 — Recognizing an infinite limit

Evaluate the one- and two-sided limits of 1x\dfrac{1}{x} at x=0x=0.

xx1/x1/xxx1/x1/x
-0.01-1000.01100
-0.001-10000.0011000

Table 2.2.4: The two sides blow up in opposite directions.

Opposite infinities → DNE

limx01x=,limx0+1x=+.\lim_{x \to 0^-}\frac{1}{x}=-\infty,\qquad \lim_{x \to 0^+}\frac{1}{x}=+\infty.So limx01x\displaystyle\lim_{x \to 0}\frac{1}{x} DNE.

Graph of 1/x diverging to minus infinity on the left and plus infinity on the right of 0

Figure 2.2.9: y=1xy=\dfrac{1}{x} with a vertical asymptote at x=0x=0.

An infinite limit18 / 23
No. 19Infinite limits by power

Theorem 2.2.3 — Infinite limits from positive integers

The parity of nn sets the sign

Even nn

limxa1(xa)n=+.\lim_{x \to a}\frac{1}{(x-a)^n}=+\infty.Both sides climb to ++\infty.

Odd nn

limxa+1(xa)n=+,\lim_{x \to a^+}\frac{1}{(x-a)^n}=+\infty, limxa1(xa)n=.\lim_{x \to a^-}\frac{1}{(x-a)^n}=-\infty.

For a real number aa and a positive integer nn, either way the line x=ax = a is a vertical asymptote.

Infinite limits by power19 / 23
No. 20Finding vertical asymptotes

Example 2.2.7 & Try It Now 2.2.6

Example 2.2.7f(x)=1(x+3)4f(x)=\dfrac{1}{(x+3)^4} at x=3x=-3

Match 1(xa)n\dfrac{1}{(x-a)^n}: a=3a=-3, n=4n=4 (even). Both sides shoot to ++\infty:

limx3f(x)=+.\lim_{x \to -3} f(x) = +\infty.

The limit blows up, so x=3x=-3 is a vertical asymptote.

Try It Now 2.2.6f(x)=1(x2)3f(x)=\dfrac{1}{(x-2)^3} at x=2x=2

n=3n=3 is odd, so the sides go to opposite infinities:

limx21(x2)3=,  limx2+1(x2)3=+.\lim_{x \to 2^-}\frac{1}{(x-2)^3}=-\infty,\ \ \lim_{x \to 2^+}\frac{1}{(x-2)^3}=+\infty.

Answer: two-sided DNE; vertical asymptote at x=2x=2.

Finding vertical asymptotes20 / 23
No. 21Four behaviors on one graph

Example 2.2.8 — Reading a graph

x=4x=-4 (smooth): limx4f(x)=0\displaystyle\lim_{x \to -4} f(x) = 0, and f(4)=0f(-4)=0.

x=2x=-2 (hole): limx2f(x)=3\displaystyle\lim_{x \to -2} f(x) = 3, but f(2)f(-2) is undefined.

x=1x=1 (jump): lim=6\lim^-=6, lim+=3\lim^+=3, two-sided DNE, f(1)=6f(1)=6.

x=3x=3 (asymptote): both sides \to -\infty, f(3)f(3) undefined.

Graph of f showing a smooth point, a hole, a jump, and a vertical asymptote

Figure 2.2.10: One graph, four behaviors: smooth, hole, jump, asymptote.

Four behaviors on one graph21 / 23
No. 22The question, answered

Four behaviors, one verdict each

Where is a function headed near a point — even when the point can't be trusted? One graph holds all four answers.

Point on the graphLimit verdict
smooth (x=4)(x=-4)exists; lim=f(a)\lim=f(a)
hole (x=2)(x=-2)exists; limf(a)\lim\ne f(a)
jump (x=1)(x=1)two-sided DNE; sides clean
asymptote (x=3)(x=3)infinite; vertical asymptote

Table 2.2.5: The limit always reads the neighborhood.

When the neighborhood agrees, the limit exists; when it splits or blows up, we don't stop at "DNE" — we name how.

Graph of f showing a smooth point, a hole, a jump, and a vertical asymptote

Figure 2.2.10: The four verdicts, all on one graph.

The question, answered22 / 23
No. 23Colophon

Headed, not
arrived.

A limit reads where a function is heading near a point — through a hole, up to a jump, or off to ±\pm\infty. When the neighborhood agrees the limit exists; when it splits or blows up, we name exactly how it fails.

Next: §2.3 The Limit Laws — computing limxaf(x)\displaystyle\lim_{x\to a}f(x) exactly, no table or graph required.

Summary23 / 23