Introduction to Statistics · Chapter 5 · The Normal Distribution
Every normal distribution can be converted into one universal ruler — the z-score — so values from entirely different scales can be compared directly.
bookSHelf · Introduction to Statistics · §5.1 · a self-paced section
Learning objectives — by the end of this section you will be able to
§5.1.1 — reading the formula, piece by piece
The numerator x−μ measures how far a value sits from the center, in the original units — positive above the mean, negative below. The denominator σ asks how that gap compares to the distribution's own typical spread.
Subtracting recenters the distribution at zero; dividing rescales it so one unit of spread becomes one unit of measurement. Together, that is what makes the score portable — a count of standard deviations, not a count of centimeters.
§5.1.1 — the target of every standardization
Definition 5.1.1 — Standard Normal Distribution
The standard normal distribution is the normal distribution with mean zero and standard deviation one, written Z∼N(0,1). Its values are called standardized values, or z-scores.
The transformation
z=σx−μturns X∼N(μ,σ) into Z∼N(0,1).
Definition 5.1.1: Standardizing changes the ruler under the curve, not the curve.
Insight — one ruler for every measurement
A change of units, not a new idea
A z-score is a change of units, the way converting to meters lets you compare a Canadian road sign with an American one. Once both values are in standard deviations, the original scales stop mattering and you can put them side by side.
§5.1.1 — the working formula
Definition 5.1.2 — z-Score
If X∼N(μ,σ), then the z-score of a value x is
z=σx−μDefinition 5.1.2: The z-score is the number of standard-deviation steps from the mean to the value.
Rearranging the same equation gives you the trip back: x=μ+zσ — the form to reach for whenever a problem hands you a standardized score and asks what it was before standardizing.
Your turn — substitute and simplify
Try It Now 5.1.1 — a single z-score
What is the z-score of x, when x=1 and X∼N(12,3)?
Answer: z=31−12=3−11≈−3.67 The value x=1 sits about 3.67 standard deviations below the mean of 12 — far out in the left tail.
Worked example — the sign says which side
Worked Example 5.1.1 — X∼N(5,6)
Find and interpret the z-score for x=17, and then for x=1.
x=17: z=617−5=2 two standard deviations to the right of the mean 5. Check: μ+zσ=5+(2)(6)=17.
x=1: z=61−5≈−0.67 about 0.67 standard deviations to the left of the mean 5.
Your turn — fill in the blanks
Try It Now 5.1.2 — Camila's points per game
Camila averages 16 points a game with a standard deviation of four, so X∼N(16,4). She scores ten points in a game: z=−1.5. This tells you x=10 is ____ standard deviations to the ____ of the mean ____.
Answer: x=10 is 1.5 standard deviations to the left of the mean 16. z=410−16=4−6=−1.5
Worked example — a gain is a negative loss
Worked Example 5.1.2 — X∼N(5,2), weight lost in a month
a. Mai lost ten pounds: z=210−5=2.5 — 2.5 sd to the right of the mean five.
b. Her brother gained three pounds, so x=−3: z=2−3−5=−4 — four sd to the left of the mean.
c. Y∼N(2,1), y=4: z=14−2=2 — the same z=2 as x=17 in Example 5.1.1, each two sd right of its own mean.
Your turn — both directions
Try It Now 5.1.3 — Chilean male heights, X∼N(170,6.28)
a. A male was 176 cm tall — find z. b. A male has z=−2 — find his height.
a. z=6.28176−170≈0.96 about 0.96 sd to the right of 170 cm.
b. x=170+(−2)(6.28)=157.44 cm two sd to the left of the mean.
Worked example — same distribution, both directions
Worked Example 5.1.3 — X∼N(170,6.28) cm
a. A male was 168 cm tall — find z. b. A male has z=1.27 — find his height.
a. z=6.28168−170≈−0.32 0.32 sd to the left of the mean 170.
b. x=170+(1.27)(6.28)≈177.98 cm 1.27 sd to the right of the mean.
Your turn — comparing two scores
Try It Now 5.1.4 — SAT verbal, X∼N(496,114)
Find the z-scores for x1=325 and x2=366.21. Which score sits further from the mean?
z1=114325−496=−1.5z2=114366.21−496≈−1.14 Answer: both are below the mean, and 325 sits deeper in the left tail than 366.21 does.
Worked example — two different populations, one shared answer
Worked Example 5.1.4 — Y∼N(172.36,6.34) [1984–85], X∼N(170,6.28) [2009–10]
Find the z-scores for x=160.58 cm and y=162.85 cm.
6.28160.58−170=−1.56.34162.85−172.36=−1.5 Answer: the raw heights differ by more than 2 cm, from two distributions with different centers and spreads — but both standardize to z=−1.5. Relative to the population each was drawn from, the two males were equally short.
Try it in rāSHio — proving a shared z-score
Take it on the panel, not on faith
Example 5.1.4 claims the two heights sit at the same place in their own distributions. Choose Distributions → Normal, pick Left, and enter mean 170, standard deviation 6.28, value 160.58; then run it again with 172.36, 6.34, and 162.85 — the same area comes back both times, which is what a shared z-score of −1.5 actually means.
§5.1.1 — the panel, in motion
Figure 5.1.1: Reading a left-tail area in rāSHio: Distributions → Normal, demonstrated on X∼N(100,15) with a cutoff at 115 — the panel's twin axes label that point in x-units and in z at once.
§5.1.2 — reading the curve
The curve is tallest in the middle, so most of the area is accounted for early: going from one standard deviation to two only buys another 27 percentage points, and two to three buys about 4.7 more.
That is what makes a z-score past 3 genuinely remarkable. The exact areas are 68.27%, 95.45%, and 99.73% — a problem quoting those longer figures is still asking about the same three bands.
§5.1.2 — three bands, every normal distribution
Definition 5.1.3 — The Empirical Rule
Figure 5.1.2: The normal curve divided at μ and at each standard deviation out to 3σ.
Also known as the 68–95–99.7 rule. The z-scores at each edge are exactly ±1, ±2, and ±3.
Context Pause — where "1 in 20" comes from
Two standard deviations, one rule of thumb
The 95% band in the rule is why researchers so often treat two standard deviations as the line between ordinary and surprising. Anything past 2σ happens to about one observation in twenty — rare enough to be worth a second look.
Your turn — the 68% band
Try It Now 5.1.5 — X∼N(25,5)
Between what values of x do 68% of the values lie?
Answer: 25−(1)(5)=2025+(1)(5)=30 about 68% of the values lie between x=20 and x=30.
Worked example — all three bands at once
Worked Example 5.1.5 — X∼N(50,6)
| Band | Lower | Upper | z-scores |
|---|---|---|---|
| 68% | 44 | 56 | −1, +1 |
| 95% | 38 | 62 | −2, +2 |
| 99.7% | 32 | 68 | −3, +3 |
Try it in rāSHio — the exact areas behind the rule
Rounded bands, exact areas
The three bands in Example 5.1.5 are rounded areas, and rāSHio will hand you the exact ones. Choose Distributions → Normal, pick Between, set mean 50 and standard deviation 6, then read the area for 44–56, then 38–62, then 32–68 — 0.6827, 0.9545, and 0.9973, the numbers the 68-95-99.7 rule rounds off.
Your turn — an entrance exam
Try It Now 5.1.6 — μ=52, σ=11 points
About 68%, 95%, and 99.7% of scores lie between what two values, respectively?
41–63 (z=∓1) · 30–74 (z=∓2) · 19–85 (z=∓3)
Worked example — the rule, in centimeters
Worked Example 5.1.6 — Y∼N(172.36,6.34) cm
| Band | Lower (cm) | Upper (cm) | z-scores |
|---|---|---|---|
| 68% | 166.02 | 178.70 | −1, +1 |
| 95% | 159.68 | 185.04 | −2, +2 |
| 99.7% | 153.34 | 191.38 | −3, +3 |
Key Terminology — the vocabulary this section put to work
standard normal distribution — the normal distribution with mean zero and standard deviation one, written Z∼N(0,1).
z-score — the number of standard deviations a value lies above or below the mean of its own distribution, z=(x−μ)/σ.
standardized value — a value re-expressed as a z-score, so that distributions on different scales can be compared directly.
Empirical Rule — for a normal distribution, about 68%, 95%, and 99.7% of the data lie within one, two, and three standard deviations of the mean; also called the 68-95-99.7 rule.
The headline result
The Empirical Rule: 68 – 95 – 99.7
Within one, two, and three standard deviations of the mean, in any normal distribution — once every value is standardized to the same Z∼N(0,1) ruler.
The same z-score formula, z=(x−μ)/σ, is what makes the rule apply everywhere at once: standardize a value first, and its position under these three bands never depends on the original units.
† These are the rounded approximations; the exact areas are 68.27%, 95.45%, and 99.73% — both forms describe the same three bands.
§5.1 — conclusions
z=(x−μ)/σ converts any normal value into a universal ruler measured in standard deviations, so values from differently scaled distributions become directly comparable — same z-score, same relative position.
The Empirical Rule only covers whole standard deviations — 1, 2, and 3σ. For anything in between, or a probability more exact than three rounded bands, use rāSHio's Distributions → Normal panel instead.
Next: §5.2 — Using the Normal Distribution, where the z-score becomes the tool for reading probabilities off any cutoff. Back to start.